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3.6 .. A dog running in an open field has components of velocityvx = 2.6 m>s and vy = -1.8 m>s at t1 = 10.0 s. For the timeinterval from t1 = 10.0 s to t2 = 20.0 s the average accelerationof the dog has magnitude 0.45 m>s2 and direction 31.0_ measuredfrom the +x@axis toward the +y@axis. At t2 = 20.0 s (a) what arethe x- and y-components of the dog’s velocity? (b) What are themagnitude and direction of the dog’s velocity? (c) Sketch the velocityvectors at t1 and t2. How do these two vectors differ? https://jjthetutor.com/3-6-a-dog-running-in-an-open-field-has-components-of-velocityvx-2-6-ms-and-vy-1-8-ms-at-t1-10-0-s-for-the-timeinterval-from-t1-10-0-s-to-t2-20-0-s-the-average-accelerationof-the-d/
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